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HCID 66687731, 화합물 → 1-[5-(3-Bromo-5-methoxy-phenyl)-1-(3-pyridyl)pyrazole-3-carbonyl]imidazolidin-4-one

HRID 930098
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HRID 930098 반응식
[Br:1][C:2]1[CH:3]=[C:4]([C:10]2[N:14]([C:15]3[CH:16]=[N:17][CH:18]=[CH:19][CH:20]=3)[N:13]=[C:12]([C:21]([OH:23])=O)[CH:11]=2)[CH:5]=[C:6]([O:8][CH3:9])[CH:7]=1.ClC1C=C(C2N(C3C=CC=CN=3)N=C(C([N:45]3[CH2:49][C:48](=[O:50])[NH:47][CH2:46]3)=O)C=2)C=C(F)C=1.Cl.N1C=CNC1=O>>[Br:1][C:2]1[CH:3]=[C:4]([C:10]2[N:14]([C:15]3[CH:16]=[N:17][CH:18]=[CH:19][CH:20]=3)[N:13]=[C:12]([C:21]([N:45]3[CH2:49][C:48](=[O:50])[NH:47][CH2:46]3)=[O:23])[CH:11]=2)[CH:5]=[C:6]([O:8][CH3:9])[CH:7]=1
참가 물질실험 절차출처 및 근거반응 노트

참가 물질

4

반응물 3

HCID 66687731HCID 66687731, 화합물HCID 71576484HCID 71576484, 화합물HCID 896025285-(3-Bromo-5-methoxyphenyl)-1-(pyridin-3-yl)-1H-pyrazole-3-carboxylic acid

생성물 1

HCID 715665471-[5-(3-Bromo-5-methoxy-phenyl)-1-(3-pyridyl)pyrazole-3-carbonyl]imidazolidin-4-one

실험 절차

80 mg (0.21 mmol) of the compound of Example 50A is reacted analogously to the synthesis of the compound of Example 1 with 29 mg (0.24 mmol) of 4-imidazolinone-hydrochloride. 76 mg (79% of theory) of the title compound is obtained.

출처 및 근거

ORD 기록
ord-6e8213328f304e9fadd6d249dda07e62
출처 데이터셋
uspto-grants-2016_03
DOI
10.6084/m9.figshare.5104873.v1
특허 번호
US09296720B2

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