F[C:2]1[CH:3]=[N:4][N:5]([C:7]2([C:10](=[NH:14])[O:11][CH2:12][CH3:13])[CH2:9][CH2:8]2)C=1.[NH:15]1C=CN=N1>>[N:4]1[N:5]([C:7]2([C:10](=[NH:14])[O:11][CH2:12][CH3:13])[CH2:9][CH2:8]2)[N:15]=[CH:2][CH:3]=1The title compound was prepared by a method analogous to the one used for Intermediate 64, but using 1,2,3-triazole as the starting material.
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