Benzene → 1,3-Di-(3'-methoxycarbonyl-n-propyl)-5,5-diethylbarbituric acid

반응식

[CH2:1]([C:3]1([CH2:12][CH3:13])[C:8](=[O:9])[NH:7][C:6](=[O:10])[NH:5][C:4]1=[O:11])[CH3:2].Cl[CH2:15][CH2:16][CH2:17][C:18]([O:20][CH3:21])=[O:19].[C:22](=[O:25])([O-])[O-:23].[K+].[K+].[CH:28]1[CH:33]=CC=C[CH:29]=1.[CH3:34]N(C)C=O>>[CH3:21][O:20][C:18]([CH2:17][CH2:16][CH2:15][N:7]1[C:8](=[O:9])[C:3]([CH2:1][CH3:2])([CH2:12][CH3:13])[C:4](=[O:11])[N:5]([CH2:29][CH2:28][CH2:33][C:22]([O:23][CH3:34])=[O:25])[C:6]1=[O:10])=[O:19]

참가 물질

반응물 5

HCID 241Benzene

HCID 2294Barbital

HCID 6228Dimethylformamide

HCID 11430Potassium Carbonate

HCID 76612Butanoic acid, 4-chloro-, methyl ester

생성물 1

HCID 213125651,3-Di-(3'-methoxycarbonyl-n-propyl)-5,5-diethylbarbituric acid

실험 절차

18.4 g (0.1 mol) of 5,5-diethylbarbituric acid are reacted with 28.7 g (0.21 mol) of methyl γ-chlorobutyrate according to Example 1. 15.2 g (0.11 mol) of potassium carbonate powder are used as the acid acceptor and 100 ml of benzene and 100 ml of dimethylformamide are used as the solvent. The reaction is carried out exactly according to Example 1 and likewise worked up. In this manner, 38.3 g (99.7% of theory) of a clear, slightly discoloured viscous product are obtained.