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HuagongsheHuagongshe Chemistry Print Report · For research reference only
HRID 1006058Generated: October 26, 2026

Potassium Iodide → N-phenethyl-4-(2-bromo-5-methoxy-benzyl)piperidine

https://huagongshe.com/reaction/1006058

Reaction equation

Participants

RoleNameHCIDCharge
ReactantPotassium IodideHCID 4875—
ReactantPhenethyl bromideHCID 7666—
ReactantPotassium CarbonateHCID 11430—
ReactantSodium HydroxideHCID 14798—
Reactant4-(2-Bromo-5-methoxybenzyl)piperidine hydrochlorideHCID 22675334—
SolventAcetonitrileHCID 6342—
ProductN-phenethyl-4-(2-bromo-5-methoxy-benzyl)piperidineHCID 1296886558.1%

Reaction Steps

4-(2-Bromo-5-methoxybenzyl)piperidine hydrochloride (192 mg, 0.60 mmol) was neutralized with a 1N-aqueous sodium hydroxide solution, followed by extraction with diethyl ether, whereby a corresponding free compound was obtained. A mixture of the free compound, phenethyl bromide (110 mg, 0.594 mmol), potassium carbonate (250 mg, 1.81 mmol), potassium iodide (10.3 mg, 0.062 mmol) and acetonitrile (3.6 mL) was heated under reflux under nitrogen for 8 hours. After the inorganic matters were filtered off, the filtrate was concentrated under reduced pressure and the concentration residue was purified by a flash silica gel column chromatography (hexane/ethyl acetate/triethylamine=5/15/0 to 5/15/1) to obtain N-phenethyl-4-(2-bromo-5-methoxy-benzyl)piperidine (134 mg, 58%) as an oil.

Provenance & Evidence

DOI10.6084/m9.figshare.5104873.v1
Patent numberUS06787560B2
Source datasetuspto-grants-2004_09
ORD IDord-eaef8a639cbc48398ec393a6080f3b49
Source noteuspto-grants-2004_09