Sodium Hydroxide → HCID 66670079, compound
Reaction equation
[CH2:1]([O:8][C:9]([N:11]1[CH2:15][CH:14]([OH:16])[CH2:13][CH:12]1[CH2:17][C:18]1[C:26]2[C:21](=[N:22][CH:23]=[CH:24][CH:25]=2)[N:20](C(=O)C)[CH:19]=1)=[O:10])[C:2]1[CH:7]=[CH:6][CH:5]=[CH:4][CH:3]=1.[OH-].[Na+]>CO>[CH2:1]([O:8][C:9]([N:11]1[CH2:15][CH:14]([OH:16])[CH2:13][CH:12]1[CH2:17][C:18]1[C:26]2[C:21](=[N:22][CH:23]=[CH:24][CH:25]=2)[NH:20][CH:19]=1)=[O:10])[C:2]1[CH:3]=[CH:4][CH:5]=[CH:6][CH:7]=1Participants
4
Reactant 2
Product 1
Reagents, catalysts & solvents 1
Procedure
To a solution containing 71 (2.11 g, 5.36 mmol) in MeOH (30 mL) at 0° C. was added 1M NaOH (8.1 mL, 8.05 mmol) in a dropwise fashion. After 1 h, TLC analysis revealed complete consumption of 71 [EtOAc, Rf(71)=0.4; Rf(72)=0.2]. The MeOH was removed in vacuo and the residue was dissolved in EtOAc, washed with dilute aqueous HCl, water, brine, dried over anhydrous Na2SO4, filtered and concentrated to afford 1.99 g of crude 72 which was used in the next step without further purification.
Workup
- customconsumption of 71 [EtOAc, Rf(71)=0.4; Rf(72)=0.2]
- customThe MeOH was removed in vacuo
- dissolutionthe residue was dissolved in EtOAc
- washwashed with dilute aqueous HCl, water, brine
- dry with materialdried over anhydrous Na2SO4
- filtrationfiltered
- concentrationconcentrated
- customto afford 1.99 g of crude 72 which
- customwas used in the next step without further purification
Sources & evidence
- ORD record
- ord-9f349d52a2b04cc48b00f3d433d514b1
- Source dataset
- uspto-grants-2011_07
- Patent number
- US07985735B2
Reaction notes
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