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HRID1016274

反应详情

EQUATION

反应方程式

HRID 1016274 的结构方程式

REACTANTS

反应物

3
结构：COC(=O)[C@@H](N)Cc1c[nH]c2ccccc12
HCID77980

L-Tryptophan, methyl ester

C12H14N2O2

结构：CO.ClC(Cl)Cl.O
HCID21866399

未命名化合物

结构：CC[NH+](CC)CC.CC[NH+](CC)CC.Cc1cn([C@H]2C[C@H](N=[N+]=[N-])[C@@H](COP([O-])[O-])O2)c(=O)[nH]c1=O
HCID22892882

未命名化合物

PRODUCTS

生成物

1
结构：COc1ccc2[nH]cc(C[C@H](N)C(=O)OP(N)(=O)[O-])c2c1.Cc1cn([C@H]2C[C@H](N=[N+]=[N-])[C@@H](CO)O2)c(=O)[nH]c1=O
HCID131723620

未命名化合物

收率 70%

PROCEDURE

实验过程

Compound 40 (218 mg, 0.503 mmol) and tryptophan methyl ester (HCl salt, 258 mg, 1.01 mmol) were subjected to a procedure similar to that described in Example 6. Flash chromatography (SiO2, 5:2:0.25 CHCl3/MeOH/H2O containing 0.5% conc. NH4OH) gave the title compound (198 mg, 70%) as a white solid. 1H NMR (D2O, 300 MHz) 7.222 (d, J=7.9 Hz, 1H), 7.103 (d, J=8.1 Hz, 1H), 7.072 (s, 1H), 6.880 (s, 1H), 6.857 (t, J=7.7 Hz, 1H), 6.729 (t, J=7.5 Hz, 1H), 5.690 (t, J=6.6 Hz, 1H), 3.883 (m, 1H), 3.763 (m, 1H), 3.635 (m, 1H), 3.527 (m, 2H), 3.448 (s, 3H), 2.899 (m, 1H), 2.765 (m, 1H), 1.857 (m, 1H), 1.682 (m, 1H), 1.493 (s, 3H); 31P NMR (D2O, 121 MHz) 6.412; HRMS (FAB) m/z calcd for C13H20N6O8P (M+H)+ 419.1080, found 419.1103.