HRID1019589

反应详情

EQUATION

反应方程式

HRID 1019589 的结构方程式

PROCEDURE

实验过程

According to a method similar to that described in Stage 12.3, starting from 0.45 g (1.56 mmol) of 5-fluoro-1-[(3-fluorophenyl)methyl]-1H-pyrrolo[2,3-b]pyridine-2-carboxylic acid, described in the preceding stage, and 0.3 g (1.71 mmol) of 6-(3-azabicyclo[3.1.0]hex-3-yl)-3-aminopyridine, prepared in Stage 21.2, we obtain 0.47 g of the expected product.

WORKUP

后处理

  1. customprepared in Stage 21.2, we