Sodium Hydroxide → HCID 86673395, compound
Reaction equation
C([O:5][C:6](=[O:25])/[CH:7]=[CH:8]/[C:9]1[CH:14]=[C:13]([CH3:15])[C:12]([O:16][C:17]2[CH:22]=[CH:21][C:20]([OH:23])=[CH:19][N:18]=2)=[C:11]([Cl:24])[CH:10]=1)CCC.[OH-].[Na+]>CO>[Cl:24][C:11]1[CH:10]=[C:9](/[CH:8]=[CH:7]/[C:6]([OH:25])=[O:5])[CH:14]=[C:13]([CH3:15])[C:12]=1[O:16][C:17]1[CH:22]=[CH:21][C:20]([OH:23])=[CH:19][N:18]=1Participants
4
Reactant 2
Product 1
Reagents, catalysts & solvents 1
Conditions
- Temperature
- 50 °C
Procedure
To a MeOH (10 mL) solution of the ester (4.73 g) was added 5 M NaOH (2 mL), and stirred for 1 hour at 50° C., then MeOH was evaporated. The residue was dissolved in water, and acidified with 6 M HCl. The resulting precipitate was collected by filtration and dried to afford (E)-3-{3-chloro-4-[(5-hydroxypyridin-2-yl)oxy]-5-methylphenyl}prop-2-enoic acid as a pale yellow powder (3.77 g).
Workup
- customMeOH was evaporated
- dissolutionThe residue was dissolved in water
- filtrationThe resulting precipitate was collected by filtration
- customdried
Sources & evidence
- ORD record
- ord-4a98f911aabe406996f2d6de1cd11848
- Source dataset
- uspto-grants-2014_05
- Patent number
- US08722663B2
Reaction notes
Loading…