1-methyl-1H-indol-4-amine → HCID 67541032, compound

HRID 1026988Notes

Reaction equation

HRID 1026988 reaction equation
Cl[C:2]1[N:7]2[N:8]=[CH:9][C:10]([C:11]([O:13][CH2:14][CH3:15])=[O:12])=[C:6]2[N:5]=[CH:4][C:3]=1[C:16]([N:18]1[CH2:23][CH2:22][CH:21]([C:24]2[CH:29]=[CH:28][CH:27]=[CH:26][CH:25]=2)[CH2:20][CH2:19]1)=[O:17].[CH3:30][N:31]1[C:39]2[C:34](=[C:35]([NH2:40])[CH:36]=[CH:37][CH:38]=2)[CH:33]=[CH:32]1>>[CH2:14]([O:13][C:11]([C:10]1[CH:9]=[N:8][N:7]2[C:2]([NH:40][C:35]3[CH:36]=[CH:37][CH:38]=[C:39]4[C:34]=3[CH:33]=[CH:32][N:31]4[CH3:30])=[C:3]([C:16]([N:18]3[CH2:23][CH2:22][CH:21]([C:24]4[CH:29]=[CH:28][CH:27]=[CH:26][CH:25]=4)[CH2:20][CH2:19]3)=[O:17])[CH:4]=[N:5][C:6]=12)=[O:12])[CH3:15]

Participants

3

Reactant 2

HCID 221703071-methyl-1H-indol-4-amineHCID 866462907-Chloro-3-ethoxycarbonyl-6-(4-phenylpiperidine-1-carbonyl)pyrazolo[1,5-a]pyrimidine

Product 1

HCID 67541032HCID 67541032, compoundYield 90%

Procedure

In the same manner as in Example 19, step 5 and using 7-chloro-3-ethoxycarbonyl-6-(4-phenylpiperidine-1-carbonyl)pyrazolo[1,5-a]pyrimidine (0.15 g, 0.36 mmol) obtained in Example 19, step 4 and 1-methyl-4-aminoindole (0.076 g, 0.52 mmol), the title compound (0.169 g, 90%) was obtained.

Sources & evidence

ORD record
ord-6406fff19b0b41e781102362c0c9c62c
Source dataset
uspto-grants-2014_05
Patent number
US08729264B2

Reaction notes

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