6-Bromo-2-methoxynaphthalene-1-carbaldehyde → HCID 59443478, compound

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Reaction Steps

The compound is prepared by the reaction of 6-bromo-2-methoxy-1-naphthaldehyde (2 g, 7.55 mmol, 1 eq) with 3-methoxyphenylboric acid (1.3 g, 8.30 mmol, 1.1 eq) according to method A. Purification by column chromatography with hexane/ethyl acetate 1/1 as the eluent yielded the desired compound in a yield of 86%, 1.9 g.

Provenance & Evidence