HRID1036999

反应详情

EQUATION

反应方程式

HRID 1036999 的结构方程式

PROCEDURE

实验过程

The preparation of the title compound takes place in analogy to the synthesis of the compound from Example 1 starting with 82.3 mg (0.22 mmol) of the compound from Example 22A. 35.0 mg (35% of theory) of the title compound are obtained.