2-Methoxy-4-(trifluoromethoxy)benzaldehyde → HCID 67067689, compound

HRID 1037211Notes

Reaction equation

HRID 1037211 reaction equation
F[C:2]1[CH:3]=[CH:4][C:5]([O:18][CH3:19])=[C:6]([CH:8]([OH:17])[C:9]#[C:10][C:11]2[CH:16]=[CH:15][CH:14]=[CH:13][CH:12]=2)[CH:7]=1.COC1C=C([O:30][C:31]([F:34])([F:33])[F:32])C=CC=1C=O>>[CH3:19][O:18][C:5]1[CH:4]=[C:3]([O:30][C:31]([F:34])([F:33])[F:32])[CH:2]=[CH:7][C:6]=1[CH:8]([OH:17])[C:9]#[C:10][C:11]1[CH:16]=[CH:15][CH:14]=[CH:13][CH:12]=1

Participants

3

Reactant 2

HCID 37238252-Methoxy-4-(trifluoromethoxy)benzaldehydeHCID 670676721-(5-Fluoro-2-methoxy-phenyl)-3-phenyl-prop-2-yn-1-ol

Product 1

HCID 67067689HCID 67067689, compoundYield 100%

Procedure

Following the procedure used to prepare 1-(5-fluoro-2-methoxy-phenyl)-3-phenyl-prop-2-yn-1-ol, 2-methoxy-4-trifluoromethoxy-benzaldehyde was reacted to give the title compound as a pale yellow oil (650 mg, 100%). LCMS (Method B): RT=4.13 min, [M−H2O+H]+=305.

Workup

  1. customwas reacted

Sources & evidence

ORD record
ord-ea570f0bcb7742e9829af1b44418c017
Source dataset
uspto-grants-2013_10
Patent number
US08546376B2

Reaction notes

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