Methanol → 2-Fluoro-5-methoxy-4-nitrobenzoic acid
Reaction equation
[F:1][C:2]1[CH:10]=[C:9]([N+:11]([O-:13])=[O:12])[C:8](F)=[CH:7][C:3]=1[C:4]([OH:6])=[O:5].[CH3:15][OH:16]>>[F:1][C:2]1[CH:10]=[C:9]([N+:11]([O-:13])=[O:12])[C:8]([O:16][CH3:15])=[CH:7][C:3]=1[C:4]([OH:6])=[O:5]Participants
3
Conditions
- Temperature
- 45 °C
Procedure
Into a round bottom flask, 2,5-difluoro-4-nitro-benzoic acid (5.00 g, 0.0246 mol) and methanol (20.0 mL, 0.494 mol;) was added. The reaction was heated at 45° C. for one hour. The solvent was removed under vacuum. 1N HCl was added to pH 4. The solid was filtered and washed with water to give 2-fluoro-5-methoxy-4-nitro-benzoic acid as an off white solid (2.84 g, 54%). 1H-NMR (DMSO-D6, 400 MHz): δ 13.90 (bs, 1H), 8.08 (d, 1H), 7.72 (d, 1H), 3.94 (s, 3H).
Workup
- customThe solvent was removed under vacuum
- addition1N HCl was added to pH 4
- filtrationThe solid was filtered
- washwashed with water
Sources & evidence
- ORD record
- ord-a694dab604854821b7e0420c4dbcd6af
- Source dataset
- uspto-grants-2013_10
- Patent number
- US08552186B2
Reaction notes
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