2-Phenylpropionic acid → HCID 117699180, compound

HRID 1049698Notes

Reaction equation

HRID 1049698 reaction equation
[C:1]1([CH:7]([CH3:11])[C:8]([OH:10])=O)[CH:6]=[CH:5][CH:4]=[CH:3][CH:2]=1.S(Cl)(Cl)=O.[NH2:16][C:17]1[CH:22]=[CH:21][C:20]([N:23]2[C:29](=[O:30])[CH2:28][C:27](=[O:31])[NH:26][C:25]3[C:32]4[C:37]([CH:38]=[CH:39][C:24]2=3)=[CH:36][CH:35]=[CH:34][CH:33]=4)=[CH:19][CH:18]=1>>[C:1]1([CH:7]([CH3:11])[C:8]([NH:16][C:17]2[CH:22]=[CH:21][C:20]([N:23]3[C:29](=[O:30])[CH2:28][C:27](=[O:31])[NH:26][C:25]4[C:32]5[C:37]([CH:38]=[CH:39][C:24]3=4)=[CH:36][CH:35]=[CH:34][CH:33]=5)=[CH:19][CH:18]=2)=[O:10])[CH:2]=[CH:3][CH:4]=[CH:5][CH:6]=1

Participants

4

Reactant 3

HCID 102962-Phenylpropionic acidHCID 24386Thionyl ChlorideHCID 1176991675-(4-Aminophenyl)-1H-naphtho[1,2-b][1,4]diazepine-2,4(3H,5H)-dione

Product 1

HCID 117699180HCID 117699180, compoundYield 22.2%

Procedure

2-Phenylpropionic acid (30 mg, 0.2 mmol) was treated with thionyl chloride in the same manner as that of Example 13, and then by using the resultant together with 5-(4-aminophenyl)-1H-naphtho[1,2-b][1,4]diazepine-2,4(3H,5H)-dione (32 mg, 0.1 mmol) obtained in Example 1, (3), the title compound (10 mg, yield 22%) was obtained as pale brown crystals in the same manner as that of Example 1, (4).

Sources & evidence

ORD record
ord-4a47f30b13544a44a21412ea5a0ad887
Source dataset
uspto-grants-2016_07
Patent number
US09382236B2

Reaction notes

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