HRID1055673

反应详情

EQUATION

反应方程式

HRID 1055673 的结构方程式

PROCEDURE

实验过程

100 mg (0.24 mmol) of the compound of Example 9A and 66 mg (0.24 mmol) of the compound of Example 23A were reacted and worked up analogously to the procedure of Example 48A. This gave 153 mg (77% pure, 73% of theory) of the title compound.