HRID1055740

反应详情

EQUATION

反应方程式

HRID 1055740 的结构方程式

PROCEDURE

实验过程

60 mg (0.21 mmol) of the compound of Example 6A and 43 mg (0.21 mmol) of the compound of Example 44A were reacted analogously to the procedure of Example 33, except that in this case the reaction time was 16 h. This gave 31 mg (31% of theory) of the title compound.