3-(Pentafluorosulfanyl)benzoic acid → HCID 89699964, compound
Reaction equation
[O:1]([C:3]1[CH:9]=[CH:8][C:6]([NH2:7])=[CH:5][C:4]=1[N:10]1[C:17]2[N:13]([N:14]=[C:15]([C:18]3[CH:19]=[N:20][CH:21]=[CH:22][CH:23]=3)[CH:16]=2)[CH:12]=[CH:11]1)[CH3:2].[F:24][S:25]([F:38])([F:37])([F:36])([F:35])[C:26]1[CH:27]=[C:28]([CH:32]=[CH:33][CH:34]=1)[C:29](O)=[O:30]>>[CH3:2][O:1][C:3]1[CH:9]=[CH:8][C:6]([NH:7][C:29](=[O:30])[C:28]2[CH:32]=[CH:33][CH:34]=[C:26]([S:25]([F:38])([F:24])([F:35])([F:36])[F:37])[CH:27]=2)=[CH:5][C:4]=1[N:10]1[C:17]2[N:13]([N:14]=[C:15]([C:18]3[CH:19]=[N:20][CH:21]=[CH:22][CH:23]=3)[CH:16]=2)[CH:12]=[CH:11]1Participants
3
Procedure
45 mg (0.15 mmol) of the compound of Example 10A and 37 mg (0.15 mmol) of 3-(pentafluoro-λ6-sulphanyl)benzoic acid were reacted and worked up analogously to the procedure of Example 16. This gave 72 mg (91% of theory) of the title compound.
Sources & evidence
- ORD record
- ord-74f287546cc44e0db3e85476b13392a1
- Source dataset
- uspto-grants-2016_07
- Patent number
- US09394309B2
Reaction notes
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