HRID1055823

反应详情

EQUATION

反应方程式

HRID 1055823 的结构方程式

PROCEDURE

实验过程

This compound as a brown solid was prepared according to the procedure described for intermediate 705, using 5,6-dihydropyrrolo[3,4-b]pyrrol-4(1H)-one (703) as the starting material. m/z (ESI, +ve) 248.7 (M+H)+).