HRID1061642

反应详情

EQUATION

反应方程式

HRID 1061642 的结构方程式

AUXILIARIES

试剂、催化剂与溶剂

1

CONDITIONS

反应条件

温度
-78 °C

PROCEDURE

实验过程

Stannic chloride (5 mL of 1 M solution in methylene chloride, 5 mmol) was added to a stirred solution of 2-(5-fluoro-2-methoxyphenyl)propan-2-ol (2.85 g, 15.5 mmol) and 2-trimethylsilanyloxy-acrylic acid ethyl ester (23.3 mmol, 4.37 g) in anhydrous methylene chloride (45 mL) cooled to −78° C. After 7 hours with the temperature maintained in the range of −78° C. to −50° C., TLC in hexanes-EtOAc (9:1) indicated that a significant amount of starting material remained. More stannic chloride (5 mL of 1 M solution in methylene chloride, 5 mmol) was added with the temperature around −50° C. After 2 hours, all the starting material had been consumed. The reaction mixture was treated with water (100 mL), stirred for 15 minutes and diluted with methylene chloride. The methylene chloride layer was separated, washed with two 50 mL portions of the water, dried over anhydrous sodium sulfate, and concentrated in vacuo to give a light brown oil. The crude product was purified by flash column chromatography over silica gel eluting with 10% EtOAc in hexanes and a fraction corresponding to Rf=0.28 was collected to give the title compound (35%) as a light brown oil.

WORKUP

后处理

  1. temperatureAfter 7 hours with the temperature maintained in the range of −78° C. to −50° C., TLC in hexanes-EtOAc (9:1)
  2. customall the starting material had been consumed
  3. additionThe reaction mixture was treated with water (100 mL)
  4. additiondiluted with methylene chloride
  5. customThe methylene chloride layer was separated
  6. washwashed with two 50 mL portions of the water
  7. dry with materialdried over anhydrous sodium sulfate
  8. concentrationconcentrated in vacuo
  9. customto give a light brown oil
  10. customThe crude product was purified by flash column chromatography over silica gel eluting with 10% EtOAc in hexanes
  11. customa fraction corresponding to Rf=0.28 was collected