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HuagongsheHuagongshe Chemistry Print Report · For research reference only
HRID 1067148Generated: October 25, 2026

2-Chloroethanol → 4-(2-Hydroxyethoxy)benzenecarboxylic acid

https://huagongshe.com/reaction/1067148

Reaction equation

Participants

RoleNameHCIDCharge
Reactant2-ChloroethanolHCID 34—
Reactant4-Hydroxybenzoic AcidHCID 135—
ReactantHydrochloric AcidHCID 313—
ReactantPotassium IodideHCID 4875—
ReactantPotassium HydroxideHCID 14797—
SolventEthanolHCID 702—
SolventWaterHCID 962—
Product4-(2-Hydroxyethoxy)benzenecarboxylic acidHCID 431225482%

Reaction Steps

300 g of potassium hydroxide were dissolved in a mixed solution of 700 ml of ethanol and 100 ml of water. After dissolving 276 g of 4-hydroxybenzoic acid and a catalytic amount of potassium iodide in the solution, 177 g of ethylene chlorohydrin was gradually added to the mixture in a heated state followed by refluxing for about 15 hours. After distilling off ethanol from the reaction mixture obtained, the residue was added to 2 liters of water. After washing the aqueous solution obtained twice with diethyl ether, the solution was acidified by the addition of hydrochloric acid, and the precipitates thus formed were collected by filtration and dried, and recrystallized from ethanol to obtain 298 g (yield 82%) of 4-(2-hydroxyethoxy)benzoic acid.

Provenance & Evidence

DOI10.6084/m9.figshare.5104873.v1
Patent numberUS06248259B1
Source datasetuspto-grants-2001_06
ORD IDord-c99a718738294745991de78a853f8944
Source noteuspto-grants-2001_06