2,5-Hexanedione → HCID 54027701, compound
Reaction equation
[F:1][C:2]1[CH:8]=[CH:7][C:5]([NH2:6])=[CH:4][C:3]=1[N+:9]([O-:11])=[O:10].[CH3:12][C:13](=O)[CH2:14][CH2:15][C:16](=O)[CH3:17]>>[N+:9]([C:3]1[CH:4]=[C:5]([N:6]2[C:16]([CH3:17])=[CH:15][CH:14]=[C:13]2[CH3:12])[CH:7]=[CH:8][C:2]=1[F:1])([O-:11])=[O:10]Participants
3
Procedure
Prepared analogously from 4-fluoro- 3-nitroaniline and 2,5-hexanedione. Yield: 98%. Mp 99-101° C.
Sources & evidence
- ORD record
- ord-2ce798f1e16e4042801d3e2ae8faa06a
- Source dataset
- uspto-grants-1999_05
- Patent number
- US05902813
Reaction notes
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