HRID1089878

反应详情

EQUATION

反应方程式

HRID 1089878 的结构方程式

PROCEDURE

实验过程

3-Methyl-6-nitroindazole (5.31 g) and 6.93 g of 2-bromo-6-methoxybenzoic acid were subjected to reaction in the same manner as in Example 11 to obtain 1-(2-carboxy-3-methoxyphenyl)-3-methyl-6-nitroindazole (yield: 75.9%). The nitro group of the compound was reduced to give 6-amino-(2-carboxy-3-methoxyphenyl)-3-methylindazole (yield: 100%), which was then cyclized to obtain 1.83 g (28.9%) of 5-amino-7-methoxy-2-methyl-6H-pyrazolo[4,5,1-d,e]acridin-6-one.