Nitric Acid → Phenol, 4-methoxy-3-nitro-, 1-acetate
Reaction equation
[CH3:1][O:2][C:3]1[CH:8]=CC(O)=[CH:5][CH:4]=1.[N+:10]([O-:13])(O)=[O:11].[C:14]([O:17][C:18](=[O:20])[CH3:19])(=O)[CH3:15]>C(O)(=O)C>[C:18]([O:17][C:14]1[CH:5]=[CH:4][C:3]([O:2][CH3:1])=[C:8]([N+:10]([O-:13])=[O:11])[CH:15]=1)(=[O:20])[CH3:19]Participants
5
Reactant 3
Product 1
Reagents, catalysts & solvents 1
Procedure
One mole of 4-methoxy-phenol in a mixture of 300 ml acetic anhydride and 300 ml acetic acid was refluxed for 12 hours. After cooling, 54 ml of nitric acid (1.3 equivalents, fuming nitric acid, d=1.52) was added dropwise at room temperature. The temperature rose to about 70° C. and nitrous vapors appeared. After completion of the addition the mixture was left under stirring for 2 hours to give 4-methoxy-3-nitrophenyl acetate as a precipitate. Isopropyl ether (300 ml) was added and the mixture was cooled to 0° C. The precipitated material was collected and dried, giving 190 g (yield=90%), m.p. 116° C.
Workup
- temperaturewas refluxed for 12 hours
- temperatureAfter cooling
- customrose to about 70° C.
- additionAfter completion of the addition the mixture
- waitwas left
Sources & evidence
- ORD record
- ord-051d1802e388429bac00e376ee4e32c8
- Source dataset
- uspto-grants-1992_01
- Patent number
- US05082847
Reaction notes
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