HRID11002

反应详情

EQUATION

反应方程式

HRID 11002 的结构方程式

PROCEDURE

实验过程

Following a procedure similar to that for the preparation of intermediate 18e, intermediate 38a (435.9 mg, 0.76 mmol), was protected to give 418.9 mg (82%) of intermediate 38b. MS (ESI) 673.4 (M+H+), 695.3 (M+Na+).