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HuagongsheHuagongshe Chemistry Print Report · For research reference only
HRID 11014Generated: October 25, 2026

Triethylamine → 4-Amino-9-methoxypyrrolo[3,4-c]carbazole-1,3(2H,6H)-dione

https://huagongshe.com/reaction/11014

Reaction equation

Participants

RoleNameHCIDCharge
ReactantTriethylamineHCID 8471—
ReactantP,P-Diphenylphosphinic azideHCID 199401—
Reactant9-Methoxy-1,3-dioxo-1,2,3,6-tetrahydropyrrolo[3,4-c]carbazole-4-carboxylic acidHCID 11843005—
Solventtert-ButanolHCID 6386—
SolventTrifluoroacetic acid methylene chlorideHCID 21863450—
Product4-Amino-9-methoxypyrrolo[3,4-c]carbazole-1,3(2H,6H)-dioneHCID 1184300693.4%

Reaction Steps

Diphenylphosphoryl azide (1.81 mL, 8.38 mmol) was added to a mixture of the 9-methoxy-1,3-dioxo-1,2,3,6-tetrahydropyrrolo[3,4-c]carbazole-4-carboxylic acid (2.55 g, 8.22 mmol), prepared as in example 4, and Et3N (1.17 mL, 8.38 mmol) in anhydrous t-butanol (300 mL) and the mixture was refluxed under an atmosphere of nitrogen for 16 h. The solution was concentrated in vacuo and the residue partitioned between EtOAc and saturated aqueous NaHCO3. Insoluble material was removed by filtration of the two layers through Celite, washing through with more EtOAc. The organic phase was dried, the drying agent was removed and the solution was concentrated to dryness and gave a yellow solid. This material was dissolved in CH2Cl2/trifluoroacetic acid (1:1) (200 mL) and the solution was held at room temperature for 1 h. After concentration in vacuo the residue was partitioned between EtOAc and saturated aqueous NaHCO3 solution. The EtOAc solution was dried, the drying agent was removed and the solution was concentrated to dryness to give an orange solid which was adsorbed onto silica and chromatographed. Elution with ethyl acetate/petroleum ether (1:1) followed by ethyl acetate and then methanol/ethyl acetate (1:9) gave 4-amino-9-methoxypyrrolo[3,4-c]carbazole-1,3(2H,6H)-dione (6) as an orange powder (2.16 g, 93%), mp 342–345° C. 1H NMR δ [(CD3)2SO] 11.18 (s, 1H), 10.78 (br s, 1H), 8.18 (d, J=2.5 Hz, 1H), 7.29 (d, J=8.7 Hz, 1H), 7.01 (dd, J=8.7, 2.5 Hz, 1H), 6.83 (s, 1H), 6.28 (br s, 2H), 3.82 (s, 3H). Found: C, 63.05; H, 3.99; N, 14.05. C15H11N3O3, 1/2H2O requires C, 63.04; H, 4.06; N, 14.7.

Provenance & Evidence

DOI10.6084/m9.figshare.5104873.v1
Patent numberUS07094798B1
Source datasetuspto-grants-2006_08
ORD IDord-a73b7af270cf42e6b11cc84eb5367f8f
Source noteuspto-grants-2006_08