Potassium Hydroxide → HCID 20553731, compound
Reaction equation
[C:1]1([S:7]([C:9]2[CH:14]=[CH:13][C:12]([CH2:15][C:16]([CH2:18]Cl)=O)=[CH:11][CH:10]=2)=[O:8])[CH:6]=[CH:5][CH:4]=[CH:3][CH:2]=1.C([N:22]1[CH2:27][CH2:26][N:25]([C:28](=[S:30])[NH2:29])[CH2:24][CH2:23]1)=O.[OH-].[K+]>C(O)C.O>[C:1]1([S:7]([C:9]2[CH:14]=[CH:13][C:12]([CH2:15][C:16]3[N:29]=[C:28]([N:25]4[CH2:26][CH2:27][NH:22][CH2:23][CH2:24]4)[S:30][CH:18]=3)=[CH:11][CH:10]=2)=[O:8])[CH:6]=[CH:5][CH:4]=[CH:3][CH:2]=1Participants
Reactant 3
Product 1
Reagents, catalysts & solvents 2
Procedure
A solution of 14.6 g of 1-(4-phenylsulfinylphenyl)-3-chloroacetone and 8.7 g of 1-formyl-4-thiocarbamoyl piperazine, melting (Kofler) at 228° C., in 250 ml of ethanol at 90%, was boiled for one hour. There was added to the hot solution a solution of 9.3 g of KOH at 85% in 10 ml of water, and the mixture was refluxed for three hours, in order to hydrolyze the formyl protecting group. Then the solvent was evaporated off under reduced pressure, and the oily residue was taken up with 200 ml of a N hydrochloric acid solution. The insoluble matter was extracted with ether. The acid solution was alkalized with K2CO3, and the resulting base was extracted thrice with, each time, 50 ml of chloroform. The chloroform part was washed with water, then the solvent was evaporated off. There was obtained 16 g of 1-[4-(4-phenylsulfinylbenzyl)-2-thiazolyl]piperazine, as raw base, M.P. of its dihydrochloride: 158°-160° C.
Workup
- customat 228° C.
- temperaturethe mixture was refluxed for three hours, in order
- customThen the solvent was evaporated off under reduced pressure
- extractionThe insoluble matter was extracted with ether
- extractionthe resulting base was extracted thrice with, each time, 50 ml of chloroform
- washThe chloroform part was washed with water
- customthe solvent was evaporated off
Sources & evidence
- ORD record
- ord-cd31496629c64d76b745d69025094ef6
- Source dataset
- uspto-grants-1982_01
- Patent number
- US04312869
Reaction notes
Loading…