HRID1112480

反应详情

EQUATION

反应方程式

REACTANTS

反应物

结构：CCCCCCCCCCCCOc1nc(Cl)nc(OCCCCCCCCCCCC)n1

HCID590644

1,3,5-Triazine, 2-chloro-4,6-bis(dodecyloxy)-

C27H50ClN3O2

HCID10563427

[1,1':3',1''-Terphenyl]-2',5'-diol

C18H14O2

结构：CCCCCCCCCCCCCCCCCCOc1nc(Cl)nc(OCCCCCCCCCCCCCCCCCC)n1

HCID14236381

2-Chloro-4,6-bis(octadecyloxy)-1,3,5-triazine

C39H74ClN3O2

PRODUCTS

生成物

结构：CCCCCCCCCCCCCCCCCCOc1nc(OCCCCCCCCCCCCCCCCCC)nc(Oc2cc(-c3ccccc3)c(O)c(-c3ccccc3)c2)n1

HCID22764376

未命名化合物

PROCEDURE

实验过程

The preparation of the 2-chloro-4,6-distearoxy-s-triazine was carried out in the manner indicated for the 2-chlor-4,6-dilauroxy-s-triazine in Example I. Also the addition reaction with 2,6-diphenyl hydroquinone was also performed in the same manner as Examples I and II. The resulting reaction product had a melting point of 33° C.

WORKUP

后处理

customThe resulting reaction product

来源与证据

来源类型: Open Reaction Database
ORD 记录: ord-480aff825f1740098ba9a0be83416c6e
来源数据集: uspto-grants-1978_10
DOI: 10.6084/m9.figshare.5104873.v1
专利: US04122270
来源说明: uspto-grants-1978_10

反应 SMILES

Cl[C:2]1[N:7]=[C:6]([O:8][CH2:9][CH2:10][CH2:11][CH2:12][CH2:13][CH2:14][CH2:15][CH2:16][CH2:17][CH2:18][CH2:19][CH2:20][CH2:21][CH2:22][CH2:23][CH2:24][CH2:25][CH3:26])[N:5]=[C:4]([O:27][CH2:28][CH2:29][CH2:30][CH2:31][CH2:32][CH2:33][CH2:34][CH2:35][CH2:36][CH2:37][CH2:38][CH2:39][CH2:40][CH2:41][CH2:42][CH2:43][CH2:44][CH3:45])[N:3]=1.ClC1N=C(OCCCCCCCCCCCC)N=C(OCCCCCCCCCCCC)N=1.[C:79]1([C:85]2[CH:91]=[C:90]([OH:92])[CH:89]=[C:88]([C:93]3[CH:98]=[CH:97][CH:96]=[CH:95][CH:94]=3)[C:86]=2[OH:87])[CH:84]=[CH:83][CH:82]=[CH:81][CH:80]=1>>[OH:87][C:86]1[C:85]([C:79]2[CH:84]=[CH:83][CH:82]=[CH:81][CH:80]=2)=[CH:91][C:90]([O:92][C:2]2[N:7]=[C:6]([O:8][CH2:9][CH2:10][CH2:11][CH2:12][CH2:13][CH2:14][CH2:15][CH2:16][CH2:17][CH2:18][CH2:19][CH2:20][CH2:21][CH2:22][CH2:23][CH2:24][CH2:25][CH3:26])[N:5]=[C:4]([O:27][CH2:28][CH2:29][CH2:30][CH2:31][CH2:32][CH2:33][CH2:34][CH2:35][CH2:36][CH2:37][CH2:38][CH2:39][CH2:40][CH2:41][CH2:42][CH2:43][CH2:44][CH3:45])[N:3]=2)=[CH:89][C:88]=1[C:93]1[CH:94]=[CH:95][CH:96]=[CH:97][CH:98]=1