HRID1143625

反应详情

EQUATION

反应方程式

HRID 1143625 的结构方程式

REACTANTS

反应物

7

结构：CC(C)=O

Acetone

C3H6O

结构：[K+]

Potassium cation

K+

结构：O=C([O-])[O-]

Carbonate

CO3-2

结构：[I-]

Iodide ion

I-

结构：Oc1cccc2[nH]ccc12

4-Hydroxyindole

C8H7NO

结构：[Cs+]

Cesium(1+)

Cs+

2 次

结构：Cc1nc(-c2ccc(C(F)(F)F)cc2)sc1CCl

5-(Chloromethyl)-4-methyl-2-[4-(trifluoromethyl)phenyl]-1,3-thiazole

C12H9ClF3NS

PRODUCTS

生成物

1

结构：Cc1nc(-c2ccc(C(F)(F)F)cc2)sc1COc1cccc2[nH]ccc12

1H-Indole, 4-[[4-methyl-2-[4-(trifluoromethyl)phenyl]-5-thiazolyl]methoxy]-

C20H15F3N2OS