HRID1144424

反应详情

EQUATION

反应方程式

HRID 1144424 的结构方程式

REACTANTS

反应物

3

结构：c1ccncc1

Pyridine

C5H5N

结构：[Pd]

Palladium

Pd

结构：Nc1nc(-c2nn(Cc3ccccc3F)c3ncc(F)cc23)nc(N)c1[N+](=O)[O-]

2-[5-Fluoro-1-[(2-fluorophenyl)methyl]-1H-pyrazolo[3,4-b]pyridin-3-yl]-5-nitro-4,6-pyrimidinediamine

C17H12F2N8O2

PRODUCTS

生成物

1

结构：Nc1nc(-c2nn(Cc3ccccc3F)c3ncc(F)cc23)nc(N)c1N

2-[5-Fluoro-1-[(2-fluorophenyl)methyl]-1H-pyrazolo[3,4-b]pyridin-3-yl]-4,5,6-pyrimidinetriamine

C17H14F2N8