HRID1182467

反应详情

EQUATION

反应方程式

HRID 1182467 的结构方程式

AUXILIARIES

试剂、催化剂与溶剂

1

PROCEDURE

实验过程

Following the procedure described in Example 14, step 3, but substituting carboxylic acid 50b for 37 and using 1.1 equivalent of NH2OH.HCl and triethylamine each, the title compound was obtained as light yellow solid in 48% yield: 1H NMR (300 MHz, CD3OD/CDCl3=5/1) δ 7.94 (d, J=9.0 Hz, 2H), 6.95 (d, J=9.0 Hz, 2H), 3.88 (s, 3H), 2.93 (t, J=7.2 Hz, 2H), 2.11 (t, J=7.5 Hz, 2H), 1.59-1.79(m, 4H), 1.37 (m, 4H); 13C NMR (75.4 MHz, CD3OD/CDCl3=5/1) δ 24.15, 25.04, 28.59(2), 32.51, 37.88, 55.21, 113.54, 129.58, 130.20, 163.39, 171.10, 200.06.