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HRID1196354

反应详情

EQUATION

反应方程式

HRID 1196354 的结构方程式

REACTANTS

反应物

2
结构：CC(=O)O[C@@H]1CC2=C[C@@H](O)[C@H]3[C@@H]4CC[C@H](C(C)C5OCC(C)(C)CO5)[C@@]4(C)CC[C@@H]3[C@@]2(C)[C@H]2O[C@@H]12
HCID86745802

未命名化合物

结构：COC(OC)C(C)[C@H]1CC[C@H]2[C@@H]3[C@H](O)C=C4C[C@@H](OC(C)=O)[C@@H]5O[C@@H]5[C@]4(C)[C@H]3CC[C@]12C
HCID86745824

未命名化合物

PRODUCTS

生成物

1
结构：COC(=O)O[C@@H]1C=C2C[C@@H](OC(C)=O)[C@@H]3O[C@@H]3[C@]2(C)[C@H]2CC[C@]3(C)[C@@H](C(C)C(OC)OC)CC[C@H]3[C@H]12
HCID86745823

未命名化合物

收率 77%

PROCEDURE

实验过程

The procedure of Example 12 was repeated except that 45.0 mg (0.1 mmole) of 1α,2α-epoxy-7α-hydroxy-21,21-dimethoxy-20-methylpregn-5-en-3β-yl acetate was used in lieu of 49.0 mg of 20-(5,5-dimethyl-1,3-dioxan2-yl)-1α,2α-epoxy-7α-hydroxypregn-5-en-3β-yl acetate to give 39.0 mg of 1α,2α-epoxy-21,21-dimethoxy-7α-methoxycarbonyloxy-20-methylpregn-5-en-3β-yl acetate (yield: 77%).