Sodium Iodide → HCID 131716305, compound

Participants

Reaction Steps

100 mg (0.1 mmol) of p-methoxybenzyl 3-chloromethyl-7-{2-(2-tritylamino-4-thiazolyl)-2-(1-diphenylmethoxycarbonylpropyloxyimino)acetamido}-ceph-3-em-4-carboxylate-syn isomer was dissolved in 1 ml of acetone, and 0.5 ml of acetone solution containing 28 mg (0.19 mmol) of sodium iodide was added to the resulting solution at room temperature and reacted for 40 minutes. After the reaction, the solvent was distilled out, methylene chloride was added to the residue, the insoluble materials were filtrated out, and the remaining filtrate was concentrated under reduced pressure, to obtain p-methoxybenzyl 3-iodomethyl-7-{2-(2-tritylamino-4-thiazolyl)-2-(1-diphenylmethoxycarbonyl-propyloxyimino) acetamido}-ceph-3-em-4-carboxylate-syn isomer. To this was added 18 mg (0.11 mmol) of 1-(2-fluoroethyl)-4-pyridothione, and the resulting mixture was dissolved in 1 ml of chloroform and reacted for 1 hour at room temperature. After the reaction, the chloroform was distilled out under reduced pressure, and the residue was purified by silicagel-chromatography (chloroform/methanol=10/1) and dissolved in 0.4 ml of anisole, and then 1.3 ml of trifluoroacetic acid was added thereto, while cooled with ice, and reacted for 1 hour. After the reaction, isopropylether was added to the reaction solution to form a precipitate therein. After dried, 80 mg of a powder was obtained. To this was added 1 ml of water and the pH value of the resulting solution was adjusted to 7.8 with sodium hydrogencarbonate, and the solution was purified with HP-20 resin (methanol/H2O=1/4) to obtain 45 mg of the above-entitled compound.

Provenance & Evidence