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HRID1233

反应详情

EQUATION

反应方程式

HRID 1233 的结构方程式

REACTANTS

反应物

2
结构：CCOC(=O)c1ccc(C#Cc2ccc3c(c2)C(=O)CCC3(C)C)nc1
HCID15391668

未命名化合物

2 次

结构：CCOC(=O)c1ccc(C#Cc2ccc3c(c2)C(C)(C)CCC3O)cc1
HCID15391671

未命名化合物

2 次

PRODUCTS

生成物

1
结构：CCOC(=O)c1ccc(C#Cc2ccc3c(c2)C(O)CCC3(C)C)nc1
HCID18314597

未命名化合物

PROCEDURE

实验过程

Employing the same general procedure as for the preparation of ethyl 4-[(5,6,7,8-tetrahydro-5-hydroxy-8,8-dimethylnaphth-2-yl)ethynyl]benzoate (Compound 9), 700 mg (2 mmol) of ethyl 6-[(5,6,7,8-tetrahydro-8,8-dimethyl-5-oxonaphth-3-yl)ethynyl]nicotinate (Compound 4) was converted into the title compound using 60 mg (1.6 mmol) of sodium borohydride.