4-(Trifluoromethoxy)aniline → HCID 21922906, compound

HRID 1244919Notes

Reaction equation

HRID 1244919 reaction equation
[Cl:1][C:2]1[N:10]=[C:9]2[C:5]([N:6]=[CH:7][N:8]2[CH:11]2[CH2:15][CH2:14][O:13][CH2:12]2)=[C:4](Cl)[N:3]=1.[F:17][C:18]([F:28])([F:27])[O:19][C:20]1[CH:25]=[CH:24][C:23]([NH2:26])=[CH:22][CH:21]=1>C(O)CCC>[Cl:1][C:2]1[N:10]=[C:9]2[C:5]([N:6]=[CH:7][N:8]2[CH:11]2[CH2:15][CH2:14][O:13][CH2:12]2)=[C:4]([NH:26][C:23]2[CH:24]=[CH:25][C:20]([O:19][C:18]([F:17])([F:27])[F:28])=[CH:21][CH:22]=2)[N:3]=1

Participants

4

Reactant 2

HCID 6008484-(Trifluoromethoxy)anilineHCID 21923063HCID 21923063, compound

Product 1

HCID 21922906HCID 21922906, compoundYield 23.4%

Reagents, catalysts & solvents 1

HCID 2631-ButanolSolvent

Procedure

The operation is carried out as in Stage 2 of Example 2 starting from 200 mg (0.77 mmoles) of the product obtained in Stage 1 of Example 2 and 3 ml of butanol and using 0.130 ml of 4-(trifluoromethoxy)-benzenamine (0.96 mmoles) in place of the benzylamine. In this way 72 mg of expected product is obtained in the form of white crystals.

Sources & evidence

ORD record
ord-2cce49028297488980d9e25c3c7ec51b
Source dataset
uspto-grants-2006_10
Patent number
US07122669B1

Reaction notes

Loading…