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HuagongsheHuagongshe Chemistry Print Report · For research reference only
HRID 1250308Generated: November 1, 2026

Sodium Iodide → HCID 15549658, compound

https://huagongshe.com/reaction/1250308

Reaction equation

Participants

RoleNameHCIDCharge
ReactantSodium IodideHCID 5238—
ReactantTriethylamineHCID 8471—
Reactant1-(2-Pyrimidinyl)piperazineHCID 88747—
ReactantFumarateHCID 5460307—
ReactantHCID 15542506HCID 15542506—
SolventWaterHCID 962—
SolventDimethylformamideHCID 6228—
ProductHCID 15549658HCID 1554965867%

Reaction Steps

14 mg of the compound of Example 1 was dissolved in 5 ml of dimethylformamide, 13 mg (1.5 equivalents) of 1-(2-pyrimidinyl)piperazine, 16 mg (2 equivalents) of sodium iodide, and 11 mg (2 equivalents) of triethylamine. were added, and the resultant mixture was agitated at 90° C. for 10 hours. This was allowed to cool, then water was added and extraction was performed twice with ethyl acetate. The entire organic layer was washed with an aqueous solution of sodium hydrogencarbonate, water, and saturated saline, then was dried with anhydrous magnesium sulfate. The solvent was distilled off and the resultant crude product was refined with silica gel column chromatography (methylene chloride:methanol=30:1) to obtain the above-referenced compound in an amount of 14 mg (yield of 67%). Note that the fumarate can be obtained by an ordinary method, then making it into an amorphous powder.

Provenance & Evidence

DOI10.6084/m9.figshare.5104873.v1
Patent numberUS06337397B1
Source datasetuspto-grants-2002_01
ORD IDord-b7802e3cef0f4f7caa1d12ab3a0d8d73
Source noteuspto-grants-2002_01