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HuagongsheHuagongshe Chemistry Print Report · For research reference only
HRID 1252797Generated: November 2, 2026

Methyl iodide → 2-(2-Fluoro-4-methoxyphenyl)-2-propanol

https://huagongshe.com/reaction/1252797

Reaction equation

Participants

RoleNameHCIDCharge
ReactantMethyl iodideHCID 6328—
ReactantAmmonium ChlorideHCID 25517—
Reactant2'-Fluoro-4'-methoxyacetophenoneHCID 592821—
ReactantMagnesiumHCID 5462224—
SolventDiethyl EtherHCID 3283—
Product2-(2-Fluoro-4-methoxyphenyl)-2-propanolHCID 1349384480.9%

Reaction Steps

17.75 g (0.125 mole) methyliodide are dissolved in diethylether and the resulting solution is added dropwise with stirring to 3.04 g magnesium chips in 15 ml anhydrous ether. The mixture is then heated under reflux for 30 minutes, followed by the dropwise addition with stirring of a solution of 16.82 g (0.1 mole) 2-fluoro-4-methoxy-acetophenone in diethylether. After heating under reflux for 2 hours, the reaction mixture is cooled, poured onto ice and the corresponding deposit dissolved by addition of aqueous NH4Cl solution. The ether phase is separated off, the aqueous phase is extracted with ether, the combined ether phases are washed with aqueous solutions of NaHSO3, NaHCO3 and then with pure water, dried over Na2SO4 and the ether removed. Distillation of the residual oil in a high vacuum gives 14.9 g 2-(2-fluoro-4-methoxyphenyl)-2-propanol.

Provenance & Evidence

DOI10.6084/m9.figshare.5104873.v1
Patent numberUS04745233
Source datasetuspto-grants-1988_05
ORD IDord-5b92d93daf3f4b858717dc80c624a6c3
Source noteuspto-grants-1988_05