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HuagongsheHuagongshe Chemistry Print Report · For research reference only
HRID 1253661Generated: November 3, 2026

Lithium Hydroxide → 3-(4-chloro-3-oxo-1,2-dihydro-isoindol-2-yl)-2,3-dihydro-1H-indene-5-carboxylic acid

https://huagongshe.com/reaction/1253661

Reaction equation

Participants

RoleNameHCIDCharge
ReactantLithium HydroxideHCID 3939—
Reactant3-(4-chloro-3-oxo-1,2-dihydro-isoindol-2-yl)-2,3-dihydro-1H-indene-5-carboxylic acid methyl esterHCID 59505434—
SolventAcetoneHCID 180—
SolventMethanolHCID 887—
SolventWaterHCID 962—
Product3-(4-chloro-3-oxo-1,2-dihydro-isoindol-2-yl)-2,3-dihydro-1H-indene-5-carboxylic acidHCID 5950523766%

Reaction Conditions

Temperature25 °C

Reaction Steps

LiOH (5 equiv.) was added to a suspension of 3-(4-chloro-3-oxo-1,2-dihydro-isoindol-2-yl)-2,3-dihydro-1H-indene-5-carboxylic acid methyl ester (D-01) (11.75 mmol) in methanol (90 ml) and water (30 ml) and the reaction mixture was stirred at 25° C. for 72 h. Methanol was distilled off, the aqueous residue was acidified with 1N HCl and the mixture was filtered. The white solid obtained was taken up in a mixture of 350 ml of acetone and 50 ml of methanol and the mixture was stirred for 1 h. After filtration, the white solid was dried in vacuo to obtain 3-(4-chloro-3-oxo-1,2-dihydro-isoindol-2-yl)-2,3-dihydro-1H-indene-5-carboxylic acid (G-01). Yield: 66%

Provenance & Evidence

DOI10.6084/m9.figshare.5104873.v1
Patent numberUS08455475B2
Source datasetuspto-grants-2013_06
ORD IDord-9837685c48ed4d20bf1f3a7c491b6fb5
Source noteuspto-grants-2013_06