p-Fluoronitrobenzene → HCID 57378675, compound

HRID 1258887Notes

Reaction equation

HRID 1258887 reaction equation
[F:1][C:2]1[CH:7]=[CH:6][CH:5]=[CH:4][C:3]=1[C:8]1[N:9]=[N:10][N:11]([CH3:18])[C:12]=1[C:13]1[N:14]=[CH:15][NH:16][CH:17]=1.F[C:20]1[CH:25]=[CH:24][C:23]([N+:26]([O-:28])=[O:27])=[CH:22][CH:21]=1>>[F:1][C:2]1[CH:7]=[CH:6][CH:5]=[CH:4][C:3]=1[C:8]1[N:9]=[N:10][N:11]([CH3:18])[C:12]=1[C:13]1[N:14]=[CH:15][N:16]([C:20]2[CH:25]=[CH:24][C:23]([N+:26]([O-:28])=[O:27])=[CH:22][CH:21]=2)[CH:17]=1

Participants

3

Reactant 2

HCID 9590p-FluoronitrobenzeneHCID 178481992HCID 178481992, compound

Product 1

HCID 57378675HCID 57378675, compoundYield 95%

Procedure

As described for example 8e, 4-(2-fluorophenyl)-5-(1H-imidazol-4-yl)-1-methyl-1H-1,2,3-triazole (70 mg, 0.29 mmol), was converted, using 1-fluoro-4-nitrobenzene instead of 4-fluorobenzotrifluoride, to the title compound (100 mg, 95%) which was obtained as a yellow solid. MS: m/e=365.1 [M+H]+.

Sources & evidence

ORD record
ord-52e5280deda74ca4be185268c24141ba
Source dataset
uspto-grants-2013_06
Patent number
US08466181B2

Reaction notes

Loading…