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HRID1261253

反应详情

EQUATION

反应方程式

HRID 1261253 的结构方程式

REACTANTS

反应物

3
结构：O=[N+]([O-])c1cc(Cl)c(O)c(Cl)c1
HCID12066

Phenol, 2,6-dichloro-4-nitro-

C6H3Cl2NO3

结构：O=C(c1cc2nccc(Cl)c2s1)N1CCCC1
HCID11173165

未命名化合物

结构：CN(C)C(=O)c1cc2nccc(Oc3ccc([N+](=O)[O-])cc3F)c2s1
HCID59424475

未命名化合物

PRODUCTS

生成物

1
结构：O=C(c1cc2nccc(Oc3c(Cl)cc([N+](=O)[O-])cc3Cl)c2s1)N1CCCC1
HCID59424694

未命名化合物

收率 69%

PROCEDURE

实验过程

Starting from the compound 139 and following the procedure described above for the synthesis of compound 6 (scheme 1, example 1) but replacing 2-fluoro-4-nitrophenol with 2,6-dichloro-4-nitrophenol, title compound 140 was obtained in 69% yield. LRMS (M+1) 438.0 (100%), 439.1 (20%), 440.1 (70%).