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HRID1261265

反应详情

EQUATION

反应方程式

HRID 1261265 的结构方程式

REACTANTS

反应物

4
结构：O=[N+]([O-])c1ccc(O)c(F)c1
HCID9825

2-Fluoro-4-nitrophenol

C6H4FNO3

结构：O=[N+]([O-])c1ccc(O)cc1Cl
HCID10283

Phenol, 3-chloro-4-nitro-

C6H4ClNO3

结构：Clc1ncnc2ccsc12
HCID2735821

4-Chlorothieno[3,2-d]pyrimidine

C6H3ClN2S

结构：O=C(NCCN1CCOCC1)c1cc2ncnc(Oc3ccc([N+](=O)[O-])cc3F)c2s1
HCID59424553

未命名化合物

PRODUCTS

生成物

1
结构：O=[N+]([O-])c1ccc(Oc2ncnc3ccsc23)cc1Cl
HCID47446362

未命名化合物

收率 72%

PROCEDURE

实验过程

Starting from the chloride 20 (scheme 4) and following the procedure described above for the synthesis of compound 24 (scheme 4, example 22) remplacing 2-fluoro-4-nitrophenol with 3-chloro-4-nitrophenol, title compound 171 was obtained in 72% yield. LRMS (M+1) 307.7 (100%).