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HuagongsheHuagongshe Chemistry Print Report · For research reference only
HRID 1261515Generated: November 3, 2026

Iodoethane → 4-Bromo-2-(1,1-dimethylethyl)-N,N-diethylbenzenamine

https://huagongshe.com/reaction/1261515

Reaction equation

Participants

RoleNameHCIDCharge
ReactantIodoethaneHCID 6340—
ReactantTetrahydrofuranHCID 8028—
ReactantSodium hydrideHCID 24758—
ReactantAmmonium ChlorideHCID 25517—
Reactant4-bromo-2-tert-butylphenylamineHCID 11959000—
SolventDimethyl SulfoxideHCID 679—
Product4-Bromo-2-(1,1-dimethylethyl)-N,N-diethylbenzenamineHCID 6667196391%

Reaction Steps

6.9 g (0.17 mol) of sodium hydride are suspended in 200 mL of tetrahydrofuran. 13 g (57 mmol) of 4-bromo-2-tert-butylaniline are added, along with 200 mL of dimethyl sulfoxide, added slowly. The mixture turns blue and, after 30 minutes, 13 mL (0.17 mol) of ethyl iodide are added and the reaction medium, which has turned white, is stirred at room temperature for 13 hours. The reaction medium is then poured into saturated ammonium chloride solution and extracted with ethyl acetate, and the organic phase is then washed twice with water. It is dried and then concentrated to dryness. The residue is purified by chromatography on silica gel (eluent: 90/10 heptane/ethyl acetate). 14.8 g of (4-bromo-2-tert-butylphenyl)diethylamine are obtained (yield=91%) in the form of a yellow oil.

Provenance & Evidence

DOI10.6084/m9.figshare.5104873.v1
Patent numberUS08470871B2
Source datasetuspto-grants-2013_06
ORD IDord-f96b34d3a4034574a4881682bfa4bead
Source noteuspto-grants-2013_06