4-Fluoroaniline → HCID 18613760, compound

Participants

Reaction Steps

The same procedures as in Step 2 of Example 3 above were repeated using 5,6-dimethyl-2-chloro-(1-methyl-5-fluoro-1,2,3,4-tetrahydroisoquinolin-2-yl)pyrimidine (0.1 g, 0.33 mmol) prepared in Step 1 above, dimethylformamide (5 ml), and 4-fluoroaniline (0.08 ml, 0.84 mmol) to afford 75 mg (54.5 %) of the titled compound.

Provenance & Evidence