4-Fluoroaniline → HCID 18613768, compound

Participants

Reaction Steps

The same procedures as in Step 2 of Example 3 above were repeated using 5,6-dimethyl-2-chloro-4-(1-methyl-5-chloro- 1,2,3,4-tetrahydroisoquinolin-2-yl)pyrimidine (0.1 g, 0.31 mmol) prepared in Step 1 above, dimethylformamide (5 ml), and 4-fluoroaniline (0.07 ml, 0.74 mmol) to afford 67 mg (50%) of the titled compound.

Provenance & Evidence