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HuagongsheHuagongshe Chemistry Print Report · For research reference only
HRID 1276192Generated: October 30, 2026

Sodium Iodide → 8-(4-Methylpiperazin-1-yl)naphthalen-2-ol

https://huagongshe.com/reaction/1276192

Reaction equation

Participants

RoleNameHCIDCharge
ReactantSodium IodideHCID 5238—
ReactantNitrogen mustard hydrochlorideHCID 5935—
Reactant1-NaphtholHCID 7005—
Reactant8-Amino-2-naphthalenolHCID 8358—
ReactantAmmonium HydroxideHCID 14923—
ReactantSodium BicarbonateHCID 516892—
SolventMethanolHCID 887—
SolventAcetonitrileHCID 6342—
SolventDichloromethaneHCID 6344—
Product8-(4-Methylpiperazin-1-yl)naphthalen-2-olHCID 10800217—

Reaction Steps

To a stirring solution of 8-amino-2-naphthol (3.28 g, 20 mmol, Aldrich Chem, Co.) in 100 mL of acetonitrile was added sodium bicarbonate (7.42 g, 88 mmol), sodium iodide (6.72 g, 44 mmol) and mechlorethamine hydrochloride (4.32 g, 22 mmol). Under nitrogen, the reaction was heated to reflux and stirred for another 2 hr. The reaction mixture was then allowed to cool to room temperature and was stirred overnight. A thin layer chromatography (tlc) using methylene chloride:methanol:conc. ammonium hydroxide (90:10:1) showed the more polar product (Rf 0.25) with only a trace of the starting naphthol. Silica gel (4.5 g) was added and the reaction mixture was concentrated in vacuo to a dry purple solid. This was added to a column of silica gel (ca. 400 g) and eluted with 2 L volumes of CH2Cl2, CH2Cl2 :CH3OH (40:1), CH2Cl2 :CH3OH:conc. NH4OH (20:1:0.1) and finally 4 L of CH2Cl2 :CH3OH:conc. NH4OH (10:1:0.1). The appropriate fractions were combined to yield a purple-black solid, 5.26 g, mp 184-185° C.

Provenance & Evidence

DOI10.6084/m9.figshare.5104873.v1
Patent numberUS06166020
Source datasetuspto-grants-2000_12
ORD IDord-2dbf4d1e782e40139d72b51090c95615
Source noteuspto-grants-2000_12