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HRID1283712

反应详情

EQUATION

反应方程式

HRID 1283712 的结构方程式

REACTANTS

反应物

2
结构：COC=O
HCID7865

Methyl formate

C2H4O2

结构：Nc1n[nH]c2ccc(C(F)(F)F)cc12
HCID16736

1H-Indazol-3-amine, 5-(trifluoromethyl)- (9CI)

C8H6F3N3

PRODUCTS

生成物

1
结构：O=CNc1n[nH]c2ccc(C(F)(F)F)cc12
HCID21409159

N-[5-(Trifluoromethyl)-1H-indazol-3-yl]formamide

C9H6F3N3O

PROCEDURE

实验过程

A mixture of 5.0 g. of 3-amino-5-trifluoromethylindazole, prepared as in Example 1, and 25 ml. of methyl formate is refluxed for eight hours, then concentrated in vacuo to leave crude 3-formylamino-5-trifluoromethylindazole.

WORKUP

后处理

  1. additionA mixture of 5.0 g
  2. concentrationconcentrated in vacuo