Water → Ethyl (4Z)-8-oxo-4-octenoate
Reaction equation
[OH:1][CH:2]1[CH2:9][CH2:8][CH:7]=[CH:6][CH2:5][CH2:4][C:3]1=[O:10].[CH2:11](O)[CH3:12].C1C=CC=CC=1.C([O-])(=[O:22])C.C([O-])(=O)C.C([O-])(=O)C.C([O-])(=O)C.[Pb+4].O>CCOCC>[O:10]=[CH:3][CH2:4][CH2:5]/[CH:6]=[CH:7]\[CH2:8][CH2:9][C:2]([O:1][CH2:11][CH3:12])=[O:22]Participants
6
Reactant 4
Product 1
Reagents, catalysts & solvents 1
Procedure
To 220 mg. of 2-hydroxy-5-cycloocten-1-one in 5 ml. of 30% ethanol/benzene is added 860 mg. of 85% lead tetraacetate in portions. After about 3 hours at room temperature, water and ether are added to the reaction mixture. The aqueous phase is extracted several times with ether. The combined ether extracts are washed with 2M sodium carbonate and saturated sodium chloride solution, dried over calcium sulfate and evaporated to give ethyl (4Z)-8-oxo-4-octenoate in high purity.
Workup
- extractionThe aqueous phase is extracted several times with ether
- washThe combined ether extracts are washed with 2M sodium carbonate and saturated sodium chloride solution
- dry with materialdried over calcium sulfate
- customevaporated
Sources & evidence
- ORD record
- ord-67c0d37127484abe9efee17483f2e141
- Source dataset
- uspto-grants-1976_10
- Patent number
- US03987073
Reaction notes
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