HRID128875

反应详情

EQUATION

反应方程式

REACTANTS

反应物

$反应SMILES：COc1ccc(COC(=O)C2=C(CCl)CS[C@@H]3C(NC(=O)/C(=N\OCC(=O)OC(c4ccccc4)c4ccccc4)c4csc(NC(c5ccccc5)(c5ccccc5)c5ccccc5)n4)C(=O)N23)cc1$

HCID88421030

未命名化合物

HCID178527814

未命名化合物

HCID178527821

未命名化合物

PRODUCTS

产物

$反应SMILES：COc1ccc(COC(=O)C2=C(CSc3nc4ncccc4s3)CS[C@@H]3C(NC(=O)/C(=N\OCC(=O)OC(c4ccccc4)c4ccccc4)c4csc(NC(c5ccccc5)(c5ccccc5)c5ccccc5)n4)C(=O)N23)cc1$

HCID141566711

未命名化合物

收率 71.1%

PROCEDURE

实验过程

Using 301 mg of p-methoxybenzyl 7-{(Z)-2-(2-tritylaminothiazol-4-yl)-2-diphenylmethoxycarbonylmethoxyiminoacetamido}-3-chloromethyl-3-cephem-4-carboxylate and 60 mg of 2-mercaptothiazolo[4,5-b]pyridine in place of p-methoxybenzyl 7-{(Z)-2-(2-tritylaminothiazol-4-yl)-2-methoxyiminoacetamido}-3-chloromethyl-3-cephem-4-carboxylate and 2-mercaptothiazolo[4,5-c]pyridine, respectively, the reaction and purification were carried out in the same manner as in Example 1(a) to obtain 242 mg of the title compound in a yield of 71%.

WORKUP

后处理

customrespectively, the reaction and purification

来源与证据

来源类型: Open Reaction Database
ORD记录: ord-5ed8ebd037d448a4b5dcbf545d94fbac
来源数据集: uspto-grants-1995_11
DOI: 10.6084/m9.figshare.5104873.v1
专利号: US05464829
来源说明: uspto-grants-1995_11

反应SMILES

[C:1]([NH:20][C:21]1[S:22][CH:23]=[C:24](/[C:26](=[N:53]/[O:54][CH2:55][C:56]([O:58][CH:59]([C:66]2[CH:71]=[CH:70][CH:69]=[CH:68][CH:67]=2)[C:60]2[CH:65]=[CH:64][CH:63]=[CH:62][CH:61]=2)=[O:57])/[C:27]([NH:29][CH:30]2[C:51](=[O:52])[N:32]3[C:33]([C:39]([O:41][CH2:42][C:43]4[CH:48]=[CH:47][C:46]([O:49][CH3:50])=[CH:45][CH:44]=4)=[O:40])=[C:34]([CH2:37]Cl)[CH2:35][S:36][C@H:31]23)=[O:28])[N:25]=1)([C:14]1[CH:19]=[CH:18][CH:17]=[CH:16][CH:15]=1)([C:8]1[CH:13]=[CH:12][CH:11]=[CH:10][CH:9]=1)[C:2]1[CH:7]=[CH:6][CH:5]=[CH:4][CH:3]=1.[SH:72][C:73]1[S:74][C:75]2[C:76]([N:81]=1)=[N:77][CH:78]=[CH:79][CH:80]=2.SC1SC2C=CN=CC=2N=1>>[C:1]([NH:20][C:21]1[S:22][CH:23]=[C:24](/[C:26](=[N:53]/[O:54][CH2:55][C:56]([O:58][CH:59]([C:66]2[CH:71]=[CH:70][CH:69]=[CH:68][CH:67]=2)[C:60]2[CH:65]=[CH:64][CH:63]=[CH:62][CH:61]=2)=[O:57])/[C:27]([NH:29][CH:30]2[C:51](=[O:52])[N:32]3[C:33]([C:39]([O:41][CH2:42][C:43]4[CH:48]=[CH:47][C:46]([O:49][CH3:50])=[CH:45][CH:44]=4)=[O:40])=[C:34]([CH2:37][S:72][C:73]4[S:74][C:75]5[C:76]([N:81]=4)=[N:77][CH:78]=[CH:79][CH:80]=5)[CH2:35][S:36][C@H:31]23)=[O:28])[N:25]=1)([C:14]1[CH:19]=[CH:18][CH:17]=[CH:16][CH:15]=1)([C:8]1[CH:13]=[CH:12][CH:11]=[CH:10][CH:9]=1)[C:2]1[CH:7]=[CH:6][CH:5]=[CH:4][CH:3]=1