Sodium Iodide → 2-((2-Chloro-4-nitrophenoxy)methyl)pyridine

Participants

Reaction Conditions

Reaction Steps

2-chloro-4-nitro phenol 10 g (57.6 mmol, 1 eq), 2-pycolyl chloride hydrogen chloride 9.45 g (57.6 mmol, 1 eq) cesium carbonate 41.3 (126.8 mmol, 2.2 eq) and sodium iodide 8.64 g (57.6 mmol, 1 eq) were suspended in 200 mL acetonitrile. The reaction mixture was stirred at 60° C. for 5 h. The resulted suspension was filtered and washed with 400 mL water, yielding 2-(2-chloro-4-nitro-phenoxymethyl)-pyridine (8 g, 52%) as a red solid.

Provenance & Evidence