Sodium Hydroxide → HCID 58907033, compound
Reaction equation
C([O:3][C:4](=[O:35])[C:5]([CH3:34])([O:7][C:8]1[CH:13]=[CH:12][C:11]([CH2:14][N:15]([C:17]2[S:21][C:20]([C:22]3[CH:27]=[CH:26][C:25]([C:28]([F:31])([F:30])[F:29])=[CH:24][CH:23]=3)=[N:19][C:18]=2[CH3:32])[CH3:16])=[CH:10][C:9]=1[CH3:33])[CH3:6])C.[OH-].[Na+]>CCO>[CH3:34][C:5]([O:7][C:8]1[CH:13]=[CH:12][C:11]([CH2:14][N:15]([C:17]2[S:21][C:20]([C:22]3[CH:23]=[CH:24][C:25]([C:28]([F:30])([F:31])[F:29])=[CH:26][CH:27]=3)=[N:19][C:18]=2[CH3:32])[CH3:16])=[CH:10][C:9]=1[CH3:33])([CH3:6])[C:4]([OH:35])=[O:3]Participants
4
Reactant 2
Product 1
Reagents, catalysts & solvents 1
Conditions
- Temperature
- 60 °C
Procedure
To a solution of example 102 (50 mg, 0.5 mmol) in EtOH (20 mL) was added excess of a 1N NaOH solution and the mixture was stirred at 60° C. for 2 h. The reaction was cooled, evaporated to dryness, the residue taken up with water, neutralized with 1N HCl to pH 7 and then extracted with CH2Cl2. The organic layer was dried over Na2SO4, filtered and the solvent removed under vacuum. The residue was then chromatographed eluting with CH2Cl2 (100%) then CH2Cl2/MeOH (98/2) and finally CH2Cl2/MeOH (95/5) to afford the title compound as an oil (10 mg, 20%).
Workup
- temperatureThe reaction was cooled
- customevaporated to dryness
- extractionextracted with CH2Cl2
- dry with materialThe organic layer was dried over Na2SO4
- filtrationfiltered
- customthe solvent removed under vacuum
- customThe residue was then chromatographed
- washeluting with CH2Cl2 (100%)
Sources & evidence
- ORD record
- ord-c6c38680f5d94ca7a2696adb59326e79
- Source dataset
- uspto-grants-2007_07
- Patent number
- US07241793B2
Reaction notes
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