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HuagongsheHuagongshe Chemistry Print Report · For research reference only
HRID 130844Generated: October 26, 2026

p-Fluorophenethylamine → 5-(2-Fluoro-4-{[2-(4-fluorophenyl)ethylamino]methyl}phenoxy)pyridine-2-carboxamide

https://huagongshe.com/reaction/130844

Reaction equation

Participants

RoleNameHCIDCharge
Reactantp-FluorophenethylamineHCID 4653—
Reactant5-(2-Fluoro-4-formylphenoxy)pyridine-2-carboxamideHCID 59729937—
Product5-(2-Fluoro-4-{[2-(4-fluorophenyl)ethylamino]methyl}phenoxy)pyridine-2-carboxamideHCID 5973026439.2%

Reaction Steps

Using a method similar to Example 405, using 5-(2-fluoro-4-formylphenoxy)pyridine-2-carboxamide (Example 403, Part B) (0.040 g, 0.154 mmol) and 4-fluorophenethylamine (0.021 g. 0.154 mmol) gives the title compound (0.0231 g, 39.2%): TOF MS ES+ 384.2 (M+H)+, HRMS calcd for C21H20N3O2F2 384.1524 (M+H)+. found 384.1509, time 0.39 min; HPLC [YMC-Pack Pro C-18 (150×4.6 mm, S-5 microm), 0.1% TFA/acetonitrile in 0.1% TFA/water at 1.0 mL/min, 20-99% over 23 min], tR=7.8 min 100% purity.

Provenance & Evidence

DOI10.6084/m9.figshare.5104873.v1
Patent numberUS07381719B2
Source datasetuspto-grants-2008_06
ORD IDord-2aaf51eb3d5044fd9d5ca7f6d23029cd
Source noteuspto-grants-2008_06